Equilibrium constant homework help

K =   [CH 3 OH]  
[CO][H 2 ] 2   =         [ × 10 -8 ]        
[ × 10 -3 ][ × 10 -3 ] 2   =         [ × 10 -8 ]        
[ × 10 -3 ] × 10 -5   = × 10 -8
× 10 -8   =
By using our calculated value for [H 2 ] we calculate the same value for K as was given in the question, so we are confident our answer is correct.

Equilibrium constant homework help

equilibrium constant homework help

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